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這篇文章主要介紹“java怎么將一個(gè)有序數(shù)組按是否連續(xù)進(jìn)行分組”,在日常操作中,相信很多人在java怎么將一個(gè)有序數(shù)組按是否連續(xù)進(jìn)行分組問(wèn)題上存在疑惑,小編查閱了各式資料,整理出簡(jiǎn)單好用的操作方法,希望對(duì)大家解答”java怎么將一個(gè)有序數(shù)組按是否連續(xù)進(jìn)行分組”的疑惑有所幫助!接下來(lái),請(qǐng)跟著小編一起來(lái)學(xué)習(xí)吧!
代碼:
import java.util.Arrays; import java.util.Comparator; import java.util.List; /** * @author liyinlong * @since 2022/8/22 9:45 上午 */ public class SemTest { public static void main(String[] args) { List<Integer> list = Arrays.asList(1, 5, 8,3, 10, 11, 19, 9, 13, 4,14); list.sort(Comparator.comparing(Integer::intValue)); String convert = convert(list); System.out.println(convert); } public static String convert(List<Integer> list) { int state = 0; String result = ""; for (int i = 0; i < list.size(); i++) { if (i == list.size() - 1) { state = 2; } if (state == 0) { if (list.get(i + 1) == list.get(i) + 1) { result += Integer.toString(list.get(i)); result += "-"; state = 1; } else { result += Integer.toString(list.get(i)); result += ","; } } else if (state == 1) { if (list.get(i + 1) != list.get(i) + 1) { result += Integer.toString(list.get(i)); result += ","; state = 0; } else { result += list.get(i) + "-"; } } else { result += Integer.toString(list.get(i)); } } String[] str = result.split(","); StringBuffer sbf = new StringBuffer(); for (int stritem = 0; stritem < str.length; stritem++) { String[] sp = str[stritem].split("-"); List<String> tt = Arrays.asList(sp); if(tt.size() == 1){ sbf.append(Arrays.toString(tt.toArray())); }else{ sbf.append("[" + tt.get(0) + "—" + tt.get(tt.size()-1) + "]"); } if(stritem != str.length-1){ sbf.append(","); } } return sbf.toString(); } }
運(yùn)行結(jié)果:
到此,關(guān)于“java怎么將一個(gè)有序數(shù)組按是否連續(xù)進(jìn)行分組”的學(xué)習(xí)就結(jié)束了,希望能夠解決大家的疑惑。理論與實(shí)踐的搭配能更好的幫助大家學(xué)習(xí),快去試試吧!若想繼續(xù)學(xué)習(xí)更多相關(guān)知識(shí),請(qǐng)繼續(xù)關(guān)注億速云網(wǎng)站,小編會(huì)繼續(xù)努力為大家?guī)?lái)更多實(shí)用的文章!
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