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在Java中處理大數(shù)據(jù)量回文串時(shí),可以采用以下技巧來提高性能和效率:
public boolean isPalindrome(String s) {
int left = 0;
int right = s.length() - 1;
while (left < right) {
if (s.charAt(left) != s.charAt(right)) {
return false;
}
left++;
right--;
}
return true;
}
StringBuilder sb = new StringBuilder();
for (int i = 0; i < n; i++) {
sb.append("a");
}
String result = sb.toString();
List<String> strings = // 讀取大量字符串
boolean allPalindromes = strings.stream()
.allMatch(s -> isPalindrome(s));
Map<String, Boolean> cache = new HashMap<>();
public boolean isPalindrome(String s) {
if (cache.containsKey(s)) {
return cache.get(s);
}
boolean result = // 檢查字符串是否為回文串
cache.put(s, result);
return result;
}
ExecutorService executor = Executors.newFixedThreadPool(Runtime.getRuntime().availableProcessors());
List<Future<Boolean>> futures = new ArrayList<>();
for (String s : strings) {
Future<Boolean> future = executor.submit(() -> isPalindrome(s));
futures.add(future);
}
boolean allPalindromes = true;
for (Future<Boolean> future : futures) {
try {
allPalindromes &= future.get();
} catch (InterruptedException | ExecutionException e) {
e.printStackTrace();
}
}
executor.shutdown();
通過使用這些技巧,你可以在Java中更高效地處理大數(shù)據(jù)量回文串。
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