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C++語言支持多繼承,一個子類可以有多個父類,子類擁有所有父類的成員變量,子類繼承所有父類的成員函數(shù),子類對象可以當(dāng)作任意父類對象使用。
class Derived : public BaseA,
public BaseB,
public BaseC
{
};
通過多重繼承得到的派生類對象可能具有不同的地址。
#include <iostream>
using namespace std;
class BaseA
{
public:
BaseA(int a)
{
ma = a;
}
private:
int ma;
};
class BaseB
{
public:
BaseB(int b)
{
mb = b;
}
private:
int mb;
};
class Derived : public BaseA,public BaseB
{
public:
Derived(int a, int b, int c):BaseA(a),BaseB(b)
{
mc = c;
}
private:
int mc;
};
struct Test
{
int a;
int b;
int c;
};
int main(int argc, char *argv[])
{
Derived d(1,2,3);
cout << sizeof(d) << endl;//12
Test* p = (Test*)&d;
cout << p->a << endl;//1
cout << p->b << endl;//2
cout << p->c << endl;//3
cout << &p->a << endl;//1
cout << &p->b << endl;//2
cout << &p->c << endl;//3
BaseA* pa = &d;
BaseB* pb = &d;
//子類對象的地址、首位繼承類的成員地址
cout << &d << endl;
cout << pa << endl;
cout << &p->a <<endl;
//子類對象的地址、次位繼承類的成員地址
cout << pb << endl;
cout << &p->b << endl;
return 0;
}
上述代碼中,Derived類對象的內(nèi)存布局如下:
Derived類對象從基類繼承而來的處成員變量將根據(jù)繼承的聲明順序進行依次排布?;谫x值兼容原則,如果BaseA類型指針pa、BaseB類型指針pb都指向子類對象d,pa將得到BaseA基類成員變量ma的地址,即子類對象的地址;pb將得到BaseB類成員變量mb的地址;因此,pa與pb的地址不相同。
上述類圖中,Teacher類和Student類都會繼承People的成員,Doctor會繼承Teacher類和Student類的成員,因此Doctor將會有兩份繼承自頂層父類People的成員。
#include <iostream>
#include <string>
using namespace std;
class People
{
public:
People(string name, int age)
{
m_name = name;
m_age = age;
}
void print()
{
cout << "name: " << m_name
<< " age: " << m_age <<endl;
}
private:
string m_name;
int m_age;
};
class Teacher : public People
{
public:
Teacher(string name, int age):People(name, age)
{
}
};
class Student : public People
{
public:
Student(string name, int age):People(name, age)
{
}
};
class Doctor : public Teacher, public Student
{
public:
Doctor(string name, int age):
Teacher(name + "_1", age),
Student(name + "_2", age)
{
}
};
int main(int argc, char *argv[])
{
Doctor doc("Bauer", 30);
//doc.print();//error
//error: request for member 'print' is ambiguous
//Doctor繼承了從Teacher,Student繼承來的print函數(shù)。
//doc.People::print();//error
//error: 'People' is an ambiguous base of 'Doctor'
//People被繼承了兩次
doc.Teacher::print();//name:bauer_1 age:30
doc.Student::print();//name:bauer_2 age:30
return 0;
}
在多繼承中,保存共同基類的多份同名成員,可以在不同的數(shù)據(jù)成員中分別存放不同的數(shù)據(jù),但保留多份數(shù)據(jù)成員的拷貝,不僅占有較多的存儲空間,增加了成員的冗余,還增加了訪問的困難。C++提供了虛基類和虛繼承機制,實現(xiàn)了在多繼承中只保留一份共同成員。
C++對于菱形多繼承導(dǎo)致的成員冗余問題的解決方案是使用虛繼承。
虛繼承中,中間層父類不再關(guān)注頂層父類的初始化,最終子類必須直接調(diào)用頂層父類的構(gòu)造函數(shù)。
虛繼承的語法如下:class 派生類名:virtual 繼承方式 基類名
#include <iostream>
#include <string>
using namespace std;
class People
{
public:
People(string name, int age)
{
m_name = name;
m_age = age;
}
void print()
{
cout << "name: " << m_name
<< " age: " << m_age <<endl;
}
private:
string m_name;
int m_age;
};
class Teacher : virtual public People
{
public:
Teacher(string name, int age):People(name, age)
{
}
};
class Student : virtual public People
{
public:
Student(string name, int age):People(name, age)
{
}
};
class Doctor : public Teacher, public Student
{
public:
//最終子類必須調(diào)用頂層父類的構(gòu)造函數(shù)
Doctor(string name, int age):
People(name, age),
Teacher(name + "_1", age),
Student(name + "_2", age)
{
}
};
int main(int argc, char *argv[])
{
Doctor doc("Bauer", 30);
doc.print();//name:bauer age:30
doc.People::print();//name:bauer age:30
doc.Teacher::print();//name:bauer age:30
doc.Student::print();//name:bauer age:30
return 0;
}
上述代碼中,使用虛繼承解決了成員冗余的問題。
虛繼承解決了多繼承產(chǎn)生的數(shù)據(jù)冗余問題,但是中間層父類不再關(guān)心頂層父類的初始化,最終子類必須直接調(diào)用頂層父類的構(gòu)造函數(shù)。
上述類圖中,Derived類繼承自BaseA和BaseB類,funcA和funcB為虛函數(shù),Derived對象模型如下:
#include <iostream>
#include <string>
using namespace std;
class BaseA
{
public:
BaseA(int a)
{
m_a = a;
}
virtual void funcA()
{
cout << "BaseA::funcA()" <<endl;
}
private:
int m_a;
};
class BaseB
{
public:
BaseB(int b)
{
m_b = b;
}
virtual void funcB()
{
cout << "BaseB::funcB()" <<endl;
}
private:
int m_b;
};
class Derived : public BaseA, public BaseB
{
public:
Derived(int a, int b, int c):BaseA(a),BaseB(b)
{
m_c = c;
}
private:
int m_c;
};
struct Test
{
void* vptrA;
int a;
void* vptrB;
int b;
int c;
};
int main(int argc, char *argv[])
{
cout << sizeof(Derived) << endl;
Derived d(1,2,3);
Test* pTest = (Test*)&d;
cout << pTest->a <<endl;//1
cout << pTest->b <<endl;//2
cout << pTest->c <<endl;//3
cout << pTest->vptrA <<endl;//
cout << pTest->vptrB <<endl;//
return 0;
}
菱形繼承示例代碼如下:
#include <iostream>
#include <string>
using namespace std;
class People
{
public:
People(string name, int age)
{
m_name = name;
m_age = age;
}
void print()
{
cout << "name: " << m_name
<< " age: " << m_age <<endl;
}
private:
string m_name;
int m_age;
};
class Teacher : public People
{
string m_research;
public:
Teacher(string name, int age, string research):People(name + "_1", age + 1)
{
m_research = research;
}
};
class Student : public People
{
string m_major;
public:
Student(string name, int age,string major):People(name + "_2", age + 2)
{
m_major = major;
}
};
class Doctor : public Teacher, public Student
{
string m_subject;
public:
Doctor(string name, int age,string research, string major, string subject):
Teacher(name, age,research),Student(name, age, major)
{
m_subject = subject;
}
};
struct Test
{
string name1;
int age1;
string research;
string name2;
int age2;
string major;
string subject;
};
int main(int argc, char *argv[])
{
Doctor doc("Bauer", 30, "Computer", "Computer Engneering", "HPC");
cout << "Doctor size: " << sizeof(doc) << endl;
Test* pTest = (Test*)&doc;
cout << pTest->name1 << endl;
cout << pTest->age1 << endl;
cout << pTest->research << endl;
cout << pTest->name2 << endl;
cout << pTest->age2 << endl;
cout << pTest->major << endl;
cout << pTest->subject << endl;
return 0;
}
// output:
// Doctor size: 28
// Bauer_1
// 31
// Computer
// Bauer_2
// 32
// Computer Engneering
// HPC
上述代碼中,底層子類對象的內(nèi)存局部如下:
底層子類對象中,分別繼承了中間層父類從頂層父類繼承而來的成員變量,因此內(nèi)存模型中含有兩份底層父類的成員變量。
如果頂層父類含有虛函數(shù),中間層父類會分別繼承頂層父類的虛函數(shù)表指針,因此,底層子類對象內(nèi)存布局如下:
#include <iostream>
#include <string>
using namespace std;
class People
{
public:
People(string name, int age)
{
m_name = name;
m_age = age;
}
virtual void print()
{
cout << "name: " << m_name
<< " age: " << m_age <<endl;
}
private:
string m_name;
int m_age;
};
class Teacher : public People
{
string m_research;
public:
Teacher(string name, int age, string research):People(name + "_1", age + 1)
{
m_research = research;
}
};
class Student : public People
{
string m_major;
public:
Student(string name, int age,string major):People(name + "_2", age + 2)
{
m_major = major;
}
};
class Doctor : public Teacher, public Student
{
string m_subject;
public:
Doctor(string name, int age,string research, string major, string subject):
Teacher(name, age,research),Student(name, age, major)
{
m_subject = subject;
}
virtual void print()
{
}
};
struct Test
{
void* vptr1;
string name1;
int age1;
string research;
void* vptr2;
string name2;
int age2;
string major;
string subject;
};
int main(int argc, char *argv[])
{
Doctor doc("Bauer", 30, "Computer", "Computer Engneering", "HPC");
cout << "Doctor size: " << sizeof(doc) << endl;
Test* pTest = (Test*)&doc;
cout << pTest->vptr1 << endl;
cout << pTest->name1 << endl;
cout << pTest->age1 << endl;
cout << pTest->research << endl;
cout << pTest->vptr2 << endl;
cout << pTest->name2 << endl;
cout << pTest->age2 << endl;
cout << pTest->major << endl;
cout << pTest->subject << endl;
return 0;
}
// output:
// Doctor size: 28
// 0x405370
// Bauer_1
// 31
// Computer
// 0x40537c
// Bauer_2
// 32
// Computer Engneering
// HPC
虛繼承是解決C++多重繼承問題的一種手段,虛繼承的底層實現(xiàn)原理與C++編譯器相關(guān),一般通過虛基類指針和虛基類表實現(xiàn),每個虛繼承的子類都有一個虛基類指針(占用一個指針的存儲空間,4(8)字節(jié))和虛基類表(不占用類對象的存儲空間)(虛基類依舊會在子類里面存在拷貝,只是僅僅最多存在一份);當(dāng)虛繼承的子類被當(dāng)做父類繼承時,虛基類指針也會被繼承。
在虛繼承情況下,底層子類對象的布局不同于普通繼承,需要多出一個指向中間層父類對象的虛基類表指針vbptr。
vbptr是虛基類表指針(virtual base table pointer),vbptr指針指向一個虛基類表(virtual table),虛基類表存儲了虛基類相對直接繼承類的偏移地址;通過偏移地址可以找到虛基類成員,虛繼承不用像普通多繼承維持著公共基類(虛基類)的兩份同樣的拷貝,節(jié)省了存儲空間。
#include <iostream>
#include <string>
using namespace std;
class People
{
public:
People(string name, int age)
{
m_name = name;
m_age = age;
}
void print()
{
cout << "this: " << this <<endl;
}
private:
string m_name;
int m_age;
};
class Teacher : virtual public People
{
string m_research;
public:
Teacher(string name, int age, string research):People(name + "_1", age + 1)
{
m_research = research;
}
void print()
{
cout << "this: " << this <<endl;
}
};
class Student : virtual public People
{
string m_major;
public:
Student(string name, int age,string major):People(name + "_2", age + 2)
{
m_major = major;
}
void print()
{
cout << "this: " << this <<endl;
}
};
class Doctor : public Teacher, public Student
{
string m_subject;
public:
Doctor(string name, int age,string research, string major, string subject):
People(name, age),Teacher(name, age,research),Student(name, age, major)
{
m_subject = subject;
}
};
struct Test
{
void* vbptr_left;
string research;
void* vbptr_right;
string major;
string subject;
string name;
int age;
};
int main(int argc, char *argv[])
{
Doctor doc("Bauer", 30, "Computer", "Computer Engneering", "HPC");
cout << "Doctor size: " << sizeof(doc) << endl;
Test* pTest = (Test*)&doc;
cout << pTest->vbptr_left << endl;
cout << *(int*)pTest->vbptr_left << endl;
cout << pTest->research << endl;
cout << pTest->vbptr_right << endl;
cout << *(int*)pTest->vbptr_right << endl;
cout << pTest->major << endl;
cout << pTest->subject << endl;
cout << pTest->name << endl;
cout << pTest->age << endl;
return 0;
}
// output:
// Doctor size: 28
// 0x40539c
// 12
// Computer
// 0x4053a8
// 0
// Computer Engneering
// HPC
// Bauer
// 30
上述代碼沒有虛函數(shù),在G++編譯器打印結(jié)果如上,底層子類對象的內(nèi)存布局如下:
#include <iostream>
#include <string>
using namespace std;
class People
{
public:
People(string name, int age)
{
m_name = name;
m_age = age;
}
virtual void print()
{
cout << "this: " << this <<endl;
}
private:
string m_name;
int m_age;
};
class Teacher : virtual public People
{
string m_research;
public:
Teacher(string name, int age, string research):People(name + "_1", age + 1)
{
m_research = research;
}
void print()
{
cout << "this: " << this <<endl;
}
virtual void func1()
{}
};
class Student : virtual public People
{
string m_major;
public:
Student(string name, int age,string major):People(name + "_2", age + 2)
{
m_major = major;
}
void print()
{
cout << "this: " << this <<endl;
}
virtual void func2()
{}
};
class Doctor : public Teacher, public Student
{
string m_subject;
public:
Doctor(string name, int age,string research, string major, string subject):
People(name, age),Teacher(name, age,research),Student(name, age, major)
{
m_subject = subject;
}
void print()
{
cout << "this: " << this <<endl;
}
virtual void func3()
{}
};
struct Test
{
void* vbptr_left;
char* research;
void* vbptr_right;
char* major;
char* subject;
void* vptr_base;
char* name;
long age;
};
int main(int argc, char *argv[])
{
Doctor doc("Bauer", 30, "Computer", "Computer Engneering", "HPC");
cout << "Doctor size: " << sizeof(doc) << endl;
Test* pTest = (Test*)&doc;
cout << pTest->vbptr_left << endl;
cout << std::hex << *(int*)pTest->vbptr_left << endl;
cout << std::dec << *((int*)pTest->vbptr_left+8) << endl;
cout << std::dec << *((int*)pTest->vbptr_left+16) << endl;
cout << std::dec << *((int*)pTest->vbptr_left+24) << endl;
cout << pTest->research << endl;
cout << pTest->vbptr_right << endl;
cout << pTest->major << endl;
cout << pTest->subject << endl;
cout << pTest->vptr_base << endl;
cout << pTest->name << endl;
cout << pTest->age << endl;
return 0;
}
上述代碼中,使用了虛繼承,因此不同的C++編譯器實現(xiàn)原理不同。
對于GCC編譯器,People對象大小為char + int + 虛函數(shù)表指針,Teacher對象大小為char+虛基類表指針+A類型的大小,Student對象大小為char+虛基類表指針+A類型的大小,Doctor對象大小為char + int +虛函數(shù)表指針+char+虛基類表指針+char+虛基類表指針+char*。中間層父類共享頂層父類的虛函數(shù)表指針,沒有自己的虛函數(shù)表指針,虛基類指針不共享,因此都有自己獨立的虛基類表指針。
VC++、GCC和Clang編譯器的實現(xiàn)中,不管是否是虛繼承還是有虛函數(shù),其虛基類指針都不共享,都是單獨的。對于虛函數(shù)表指針,VC++編譯器根據(jù)是否為虛繼承來判斷是否在繼承關(guān)系中共享虛表指針。如果子類是虛繼承擁有虛函數(shù)父類,且子類有新加的虛函數(shù)時,子類中則會新加一個虛函數(shù)表指針;GCC編譯器和Clang編譯器的虛函數(shù)表指針在整個繼承關(guān)系中共享的。
G++編譯器對于類的內(nèi)存分布和虛函數(shù)表信息命令如下:
g++ -fdump-class-hierarchy main.cpp
cat main.cpp.002t.class
VC++編譯器對于類的內(nèi)存分布和虛函數(shù)表信息命令如下:cl main.cpp /d1reportSingleClassLayoutX
Clang編譯器對于類的內(nèi)存分布和虛函數(shù)表信息命令如下:clang -Xclang -fdump-record-layouts
所有的虛函數(shù)都保存在虛函數(shù)表中,多重繼承可能產(chǎn)生多個虛函數(shù)表。多繼承中,當(dāng)子類對父類的虛函數(shù)重寫時,子類的函數(shù)覆蓋父類的函數(shù)在對應(yīng)虛函數(shù)表中的虛函數(shù)位置;當(dāng)子類有新的虛函數(shù)時,新的虛函數(shù)被加到第一個基類的虛函數(shù)表的末尾。當(dāng)dynamic_cast對子類對象進行轉(zhuǎn)換時,子類和第一個基類的地址相同,不需要移動指針,但當(dāng)dynamic_cast轉(zhuǎn)換子類到其他父類時,需要做相應(yīng)的指針調(diào)整。
C++語言中,通常對指針進行類型轉(zhuǎn)換,不會改變指針的值,只會改變指針的類型(即改變編譯器對該指針指向內(nèi)存的解釋方式),但在C++多重繼承中并不成立。
#include <iostream>
using namespace std;
class BaseA
{
public:
BaseA(int value = 0)
{
data = value;
}
virtual void printA()
{
cout << "BaseA::print data = " << data << endl;
}
protected:
int data;
};
class BaseB
{
public:
BaseB(int value = 0)
{
data = value;
}
virtual void printB()
{
cout << "BaseB::print data = " << data << endl;
}
protected:
int data;
};
class Derived : public BaseA, public BaseB
{
public:
Derived(int value = 0)
{
data = value;
}
virtual void printA()
{
cout << "Derived printA data = " << data << endl;
}
virtual void printB()
{
cout << "Derived printB data = " << data << endl;
}
protected:
int data;
};
int main(int argc, char *argv[])
{
Derived* dpd = new Derived(102);
cout << dpd << endl;//0x8d1190
BaseA* bpa = (BaseA*)dpd;
cout << bpa << endl;//0x8d1190
BaseB* bpb = (BaseB*)dpd;
cout << bpb << endl;//0x8d1198
cout << (dpd == bpb) << endl;//1
return 0;
}
上述代碼中,指向Derived對象的指針轉(zhuǎn)換為基類BaseA和BaseB后,指針值并不相同。dpd指針、bpa指針與bpb指針相差8個字節(jié)的地址空間,即BaseA類虛函數(shù)表指針與data成員占用的空間。
將一個派生類的指針轉(zhuǎn)換成某一個基類指針,C++編譯器會將指針的值偏移到該基類在對象內(nèi)存中的起始位置。
cout << (dpd == bpb) << endl;//1
上述代碼打印出1,C++編譯器屏蔽了指針的差異,當(dāng)C++編譯器遇到一個指向派生類的指針和指向其某個基類的指針進行==運算時,會自動將指針做隱式類型提升以屏蔽多重繼承帶來的指針差異。
派生類對象指針轉(zhuǎn)換為不同基類對象指針時,C++編譯器會按照派生類聲明的繼承順序,轉(zhuǎn)換為第一基類時指針不變,以后依次向后偏移前一基類所占字節(jié)數(shù)。
多繼承下,指針類型轉(zhuǎn)換需要考慮this指針調(diào)整的問題。
多繼承中,如果中間層父類有兩個以上父類實現(xiàn)了虛函數(shù),會造成子類產(chǎn)生多個虛函數(shù)表指針,可以使用dynamic_cast關(guān)鍵字作類型轉(zhuǎn)換。
工程實踐中通常使用單繼承某個類和實現(xiàn)多個接口解決多繼承的問題。
代碼實例:
#include <iostream>
#include <string>
using namespace std;
class Base
{
protected:
int mi;
public:
Base(int i)
{
mi = i;
}
int getI()
{
return mi;
}
bool equal(Base* obj)
{
return (this == obj);
}
};
class Interface1
{
public:
virtual void add(int i) = 0;
virtual void minus(int i) = 0;
};
class Interface2
{
public:
virtual void multiply(int i) = 0;
virtual void divide(int i) = 0;
};
class Derived : public Base, public Interface1, public Interface2
{
public:
Derived(int i) : Base(i)
{
}
void add(int i)
{
mi += i;
}
void minus(int i)
{
mi -= i;
}
void multiply(int i)
{
mi *= i;
}
void divide(int i)
{
if( i != 0 )
{
mi /= i;
}
}
};
int main()
{
Derived d(100);
Derived* p = &d;
Interface1* pInt1 = &d;
Interface2* pInt2 = &d;
cout << "p->getI() = " << p->getI() << endl; // 100
pInt1->add(10);
pInt2->divide(11);
pInt1->minus(5);
pInt2->multiply(8);
cout << "p->getI() = " << p->getI() << endl; // 40
cout << endl;
cout << "pInt1 == p : " << p->equal(dynamic_cast<Base*>(pInt1)) << endl;
cout << "pInt2 == p : " << p->equal(dynamic_cast<Base*>(pInt2)) << endl;
return 0;
}
在程序設(shè)計中最好不要出現(xiàn)多繼承,要有也是繼承多個作為接口使用抽象類(只聲明需要的功能,沒有具體的實現(xiàn))。因為出現(xiàn)一般的多繼承本身就是一種不好的面向?qū)ο蟪绦蛟O(shè)計。
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