JAVA如何刪除字符串固定下標(biāo)字串

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需要修改的報(bào)文

當(dāng)你拿到的報(bào)文是這樣的

{
    "input": {
        "sdfsn": "23u4209350-2",
        "fsfs": "128412094",
        "sgsgsg": "15821059",
        "inssgsuplc_admdfdfdvs": "125125332",
        "dgh": "125215312",
        "dfgdfg": "215215",
        "sdhdsh": "",
        "sdfsn": "",
        "shdfshdshdsh": "shsdh",
        "sdhdsh": "shsh.0",
        "shsdhsd": "1",
        "shsdh": "1607",
        "input": {
            "data": {
                "dhfsdhsd": "235325",
                "shsdhsdh": "03",
                "dgd": "BE0445360",
                "dfhfdh": "11",
                "dshshsd": 76.56,
                "ghjrfgj": "01",
                "grjf": "234623626",
                "hjfd": "236436",
                "djfdfgjdfj": "45634",
                "exp_Content": "{"gdsg":"01","gjfj":"658568","fjfj":"5675467","ghfjfgkj":"68568","vmgfvj":"658568","gfhjgfyk":"0","fghkfghkg":"5474567"}",
                "dfjgdfj": "",
                "dfjdfjgdfj": "56745745",
                "dfgjdfgjh": 45756758,
                "jdfgjhfdgj": 0,
            }
        }
    },
    "output": {
        "output": {
            "r757": {
                "dhfsdhsd": "235325",
                "shsdhsdh": "03",
                "dgd": "BE0445360",
                "dfhfdh": "11",
                "dshshsd": 76.56,
                "ghjrfgj": "01",
                "grjf": "234623626",
                "hjfd": "236436",
                "djfdfgjdfj": "45634",
                "exp_content": "",
                "dfjgdfj": "",
                "dfjdfjgdfj": "56745745",
                "dfgjdfgjh": 45756758,
                "jdfgjhfdgj": 0,
            },
            "sdfgsdfg": [
                {
                    "sgasgag": "4673476",
                    "agasgdas": 5675467,
                    "asgasgasg": "",
                    "asdgasgas": 4567456754,
                    "dhsdsxchsdh": 54675467,
                    "sdfhsdhsdh": "5674756457"
                }
            ]
        },
        "erherth": 0,
    }
}

這一看就知道上邊的報(bào)文在postman里邊肯定會(huì)報(bào)錯(cuò)，因?yàn)閑xp_Content，因此他又沒有用到，所以你想把他刪掉。其實(shí)也沒那么難刪

也就是用到了流轉(zhuǎn)字符串。字符串固定字符查找，然后進(jìn)行字符串轉(zhuǎn)字符流，刪掉字符流中固定字符，之后再轉(zhuǎn)回來(lái)。因?yàn)樽址呀?jīng)是final了所以很多用法都是使用字符串轉(zhuǎn)字符流實(shí)現(xiàn)的

實(shí)現(xiàn)代碼如下

    private JSONObject resolveApplicationJson(HttpServletRequest request) {
        InputStream is = null;
        String json = null;
        try {
            is = request.getInputStream();
            json = IOUtils.toString(is, "UTF-8");
            json=json.replaceAll("\\r|\n|\t","");
            int index=  json.indexOf("exp_Content");
            int indexfirst=json.indexOf("{", index);
            int indexlast=json.indexOf("}",index);
            if (index!=-1 && indexlast !=-1 &&indexfirst !=-1) {
              StringBuffer stringBuffer = new StringBuffer(json);
                  stringBuffer.delete(indexfirst,indexlast+1);
                  json=stringBuffer.toString();
}
          
     
        } catch (IOException e) {
            throw new RuntimeException("CANNOT get reader from request!", e);
        } finally {
            if (is != null) {
                try {
                    is.close();
                } catch (IOException e) {
                    e.printStackTrace();
                }
            }
        }

        try {
            return new JSONObject(json);
        } catch (JSONException e) {
            throw new RuntimeException("CANOT CONVET JSON:[" + json + "] to JSONObject!", e);
        }
    }

多存在多個(gè)不符合規(guī)定的數(shù)據(jù)然后你要?jiǎng)h掉怎么操作呢？

當(dāng)你拿到的報(bào)文是這樣的。

{
    "input": {
        "sdfsn": "23u4209350-2",
        "fsfs": "128412094",
        "sgsgsg": "15821059",
        "inssgsuplc_admdfdfdvs": "125125332",
        "dgh": "125215312",
        "dfgdfg": "215215",
        "sdhdsh": "",
        "sdfsn": "",
        "shdfshdshdsh": "shsdh",
        "sdhdsh": "shsh.0",
        "shsdhsd": "1",
        "shsdh": "1607",
        "input": {
            "data": {
                "dhfsdhsd": "235325",
                "shsdhsdh": "03",
                "dgd": "BE0445360",
                "dfhfdh": "11",
                "dshshsd": 76.56,
                "ghjrfgj": "01",
                "grjf": "234623626",
                "hjfd": "236436",
                "djfdfgjdfj": "45634",
                "exp_Content": "{"gdsg":"01","gjfj":"658568","fjfj":"5675467","ghfjfgkj":"68568","vmgfvj":"658568","gfhjgfyk":"0","fghkfghkg":"5474567"}",
                "dfjgdfj": "",
                "dfjdfjgdfj": "56745745",
                "dfgjdfgjh": 45756758,
                "jdfgjhfdgj": 0,
            }
        }
    },
    "output": {
        "output": {
            "r757": {
                "dhfsdhsd": "235325",
                "shsdhsdh": "03",
                "dgd": "BE0445360",
                "exp_Content": "{"gdsg":"01","gjfj":"658568","fjfj":"5675467","ghfjfgkj":"68568","vmgfvj":"658568","gfhjgfyk":"0","fghkfghkg":"5474567"}",
                "dfhfdh": "11",
                "dshshsd": 76.56,
                "ghjrfgj": "01",
                "grjf": "234623626",
                "hjfd": "236436",
                "djfdfgjdfj": "45634",
                "exp_content": "{"gdsg":"01","gjfj":"658568","fjfj":"5675467","ghfjfgkj":"68568","vmgfvj":"658568","gfhjgfyk":"0","fghkfghkg":"5474567"}",
                "dfjgdfj": "",
                "dfjdfjgdfj": "56745745",
                "dfgjdfgjh": 45756758,
                "jdfgjhfdgj": 0,
            },
            "sdfgsdfg": [
                {
                    "sgasgag": "4673476",
                    "agasgdas": 5675467,
                    "asgasgasg": "",
                    "asdgasgas": 4567456754,
                    "dhsdsxchsdh": 54675467,
                    "sdfhsdhsdh": "5674756457"
                }
            ]
        },
        "erherth": 0,
    }
}

解決方式如下：根據(jù)需要寫出正則表達(dá)式，再使用正則看看有幾個(gè)這樣的不需要的符號(hào)，然后循環(huán)遍歷幾次，之后找到這部分，最后刪除掉。

實(shí)現(xiàn)代碼如下

# 全局變量
private static String REGEX = "exp_[c,C]ontent";

# 方式方法
Pattern p = Pattern.compile(REGEX);
        // 獲取 matcher 對(duì)象
        Matcher m = p.matcher(JSON);
        List<Integer> list = new ArrayList();
        while(m.find()){
            list.add(m.start());
        }
        int index=0;
        int indexfirst=0;
        int indexlast=0;
        for (int j = 0; j < list.size(); j++) {
             index=JSON.indexOf("exp_",indexlast);
             indexfirst=JSON.indexOf("{", index);
             indexlast=JSON.indexOf("}",index);
            StringBuffer stringBuffer =null;
            if (indexlast !=-1 &&indexfirst !=-1) {
                stringBuffer = new StringBuffer(JSON);
                stringBuffer.delete(indexfirst,indexlast+1);
            }
            JSON=stringBuffer.toString();
        }

到此，相信大家對(duì)“JAVA如何刪除字符串固定下標(biāo)字串”有了更深的了解，不妨來(lái)實(shí)際操作一番吧！這里是億速云網(wǎng)站，更多相關(guān)內(nèi)容可以進(jìn)入相關(guān)頻道進(jìn)行查詢，關(guān)注我們，繼續(xù)學(xué)習(xí)！