您好,登錄后才能下訂單哦!
這篇文章將為大家詳細(xì)講解有關(guān)Java如何實(shí)現(xiàn)一個(gè)簡(jiǎn)單的撲克牌魔術(shù),小編覺(jué)得挺實(shí)用的,因此分享給大家做個(gè)參考,希望大家閱讀完這篇文章后可以有所收獲。
用到了Scanner,for循環(huán),if-else語(yǔ)句,集合,線程的Thread.sleep()方法
import java.util.ArrayList;
import java.util.Collections;
import java.util.Scanner;
public class CardMagic {
public static void main(String[] args) {
//1.準(zhǔn)備54張牌
//新建一個(gè)集合存儲(chǔ)54張牌并打亂順序
ArrayList<String> pokers = new ArrayList<>();
//直接定義兩個(gè)數(shù)組并賦值,一個(gè)存四種花色,一個(gè)存13張牌的值(3,4,5,6,7,8,9,10,J,Q,K,A,2)
String[] kind = {"?","?","?","?"};
String[] number = {"3","4","5","6","7","8","9","10","J","Q","K","A","2"};
//先存大王小王到pokers集合中
pokers.add("大王");
pokers.add("小王");
//組裝兩個(gè)集合的數(shù)據(jù),生成帶花色的52張牌(可以用普通for循環(huán),也可以用增強(qiáng)for循環(huán)foreach)
for (int i = 0; i < kind.length; i+ +) {
for (int j = 0; j < 13; j++) {
pokers.add(kind[i]+number[j]);
}
}
System.out.println("這里有54張牌:"+pokers);//順序打印
//洗牌--打亂pokers集合里的元素順序
Collections.shuffle(pokers);//打亂順序
//再新建一個(gè)集合,用來(lái)存儲(chǔ)隨機(jī)拿出的21張牌(偽隨機(jī):其實(shí)是拿出前21張牌,但是pokers集合是隨機(jī)打亂順序的,所以每次運(yùn)行程序,拿出的前21張牌也就不一樣且亂序了)
ArrayList<String> list21 = new ArrayList<>();
for (int i = 0; i < 21; i++) {
list21.add(pokers.get(i));
}
//打印出這21張牌
System.out.println("隨機(jī)取出21張撲克牌并打亂順序:");
System.out.println(list21);
System.out.println("請(qǐng)選擇任意一張撲克牌,并記住它。【輸入小寫字母'y'繼續(xù),輸入其他任意字符結(jié)束游戲!】");
Scanner scanner1 = new Scanner(System.in);
if (scanner1.nextLine().equals("y")){
System.out.println("系統(tǒng)將這21張撲克牌均分為3疊,請(qǐng)等待...");
try {
Thread.sleep(3000);
} catch (InterruptedException e) {
e.printStackTrace();
}
}else {
System.exit(-1);
}
//定義3個(gè)集合,每個(gè)集合存儲(chǔ)7張牌
ArrayList<String> card1 = new ArrayList<>();
ArrayList<String> card2 = new ArrayList<>();
ArrayList<String> card3 = new ArrayList<>();
for (int i = 0; i < 7; i++) {
card1.add(list21.get(i));
}
for (int i = 7; i < 14; i++) {
card2.add(list21.get(i));
}
for (int i = 14; i < 21; i++) {
card3.add(list21.get(i));
}
System.out.println("第1疊:"+card1);
System.out.println("第2疊:"+card2);
System.out.println("第3疊:"+card3);
//判斷輸入
try {
Thread.sleep(1000);
} catch (InterruptedException e) {
e.printStackTrace();
}
Scanner scanner2 = new Scanner(System.in);
System.out.println("請(qǐng)告訴我你記住的牌在第幾疊~如果在第1疊請(qǐng)輸入數(shù)字1;如果在第2疊請(qǐng)輸入數(shù)字2;如果在第3疊請(qǐng)輸入數(shù)字3");
System.out.println("請(qǐng)輸入:");
//新建3個(gè)數(shù)組,分3次重新存重新按指定規(guī)則排序的21張牌
ArrayList<String> list21New1 = new ArrayList<>();
int a = scanner2.nextInt();
if (a==1){
for (int i = 0; i < 7; i++) {
list21New1.add(card2.get(i));
}
for (int i = 0; i < 7; i++) {
list21New1.add(card1.get(i));
}
for (int i = 0; i < 7; i++) {
list21New1.add(card3.get(i));
}
}else if (a==2){
for (int i = 0; i < 7; i++) {
list21New1.add(card1.get(i));
}
for (int i = 0; i < 7; i++) {
list21New1.add(card2.get(i));
}
for (int i = 0; i < 7; i++) {
list21New1.add(card3.get(i));
}
}else {
for (int i = 0; i < 7; i++) {
list21New1.add(card1.get(i));
}
for (int i = 0; i < 7; i++) {
list21New1.add(card3.get(i));
}
for (int i = 0; i < 7; i++) {
list21New1.add(card2.get(i));
}
}
card1.clear();
card2.clear();
card3.clear();
for (int i = 0; i < 21; i++) {
card1.add(list21New1.get(i));
i++;
card2.add(list21New1.get(i));
i++;
card3.add(list21New1.get(i));
}
System.out.println("第1疊:"+card1);
System.out.println("第2疊:"+card2);
System.out.println("第3疊:"+card3);
//判斷輸入
try {
Thread.sleep(1000);
} catch (InterruptedException e) {
e.printStackTrace();
}
Scanner scanner3 = new Scanner(System.in);
System.out.println("請(qǐng)告訴我你記住的牌在第幾疊~如果在第1疊請(qǐng)輸入數(shù)字1;如果在第2疊請(qǐng)輸入數(shù)字2;如果在第3疊請(qǐng)輸入數(shù)字3");
System.out.println("請(qǐng)輸入:");
int b = scanner3.nextInt();
//新建3個(gè)數(shù)組,分3次重新存重新按指定規(guī)則排序的21張牌
ArrayList<String> list21New2 = new ArrayList<>();
if (b==1){
for (int i = 0; i < 7; i++) {
list21New2.add(card2.get(i));
}
for (int i = 0; i < 7; i++) {
list21New2.add(card1.get(i));
}
for (int i = 0; i < 7; i++) {
list21New2.add(card3.get(i));
}
}else if (b==2){
for (int i = 0; i < 7; i++) {
list21New2.add(card1.get(i));
}
for (int i = 0; i < 7; i++) {
list21New2.add(card2.get(i));
}
for (int i = 0; i < 7; i++) {
list21New2.add(card3.get(i));
}
}else {
for (int i = 0; i < 7; i++) {
list21New2.add(card1.get(i));
}
for (int i = 0; i < 7; i++) {
list21New2.add(card3.get(i));
}
for (int i = 0; i < 7; i++) {
list21New2.add(card2.get(i));
}
}
card1.clear();
card2.clear();
card3.clear();
for (int i = 0; i < 21; i++) {
card1.add(list21New2.get(i));
i++;
card2.add(list21New2.get(i));
i++;
card3.add(list21New2.get(i));
}
System.out.println("第1疊:"+card1);
System.out.println("第2疊:"+card2);
System.out.println("第3疊:"+card3);
//判斷輸入
try {
Thread.sleep(1000);
} catch (InterruptedException e) {
e.printStackTrace();
}
Scanner scanner4 = new Scanner(System.in);
System.out.println("請(qǐng)告訴我你記住的牌在第幾疊~如果在第1疊請(qǐng)輸入數(shù)字1;如果在第2疊請(qǐng)輸入數(shù)字2;如果在第3疊請(qǐng)輸入數(shù)字3");
System.out.println("請(qǐng)輸入:");
//新建3個(gè)數(shù)組,分3次重新存重新按指定規(guī)則排序的21張牌
ArrayList<String> list21New3 = new ArrayList<>();
int c = scanner2.nextInt();
if (c==1){
for (int i = 0; i < 7; i++) {
list21New3.add(card2.get(i));
}
for (int i = 0; i < 7; i++) {
list21New3.add(card1.get(i));
}
for (int i = 0; i < 7; i++) {
list21New3.add(card3.get(i));
}
}else if (c==2){
for (int i = 0; i < 7; i++) {
list21New3.add(card1.get(i));
}
for (int i = 0; i < 7; i++) {
list21New3.add(card2.get(i));
}
for (int i = 0; i < 7; i++) {
list21New3.add(card3.get(i));
}
}else {
for (int i = 0; i < 7; i++) {
list21New3.add(card1.get(i));
}
for (int i = 0; i < 7; i++) {
list21New3.add(card3.get(i));
}
for (int i = 0; i < 7; i++) {
list21New3.add(card2.get(i));
}
}
System.out.println("好了,稍等片刻!讓我猜猜你記住的是什么牌......");
try {
Thread.sleep(1000);
} catch (InterruptedException e) {
e.printStackTrace();
}
System.out.println("真相永遠(yuǎn)只有一個(gè),你選的牌是"+list21New3.get(10)+"!");
System.out.println("什么?你說(shuō)我是運(yùn)氣好?不!這是“魔法”!");
}
}
關(guān)于“Java如何實(shí)現(xiàn)一個(gè)簡(jiǎn)單的撲克牌魔術(shù)”這篇文章就分享到這里了,希望以上內(nèi)容可以對(duì)大家有一定的幫助,使各位可以學(xué)到更多知識(shí),如果覺(jué)得文章不錯(cuò),請(qǐng)把它分享出去讓更多的人看到。
免責(zé)聲明:本站發(fā)布的內(nèi)容(圖片、視頻和文字)以原創(chuàng)、轉(zhuǎn)載和分享為主,文章觀點(diǎn)不代表本網(wǎng)站立場(chǎng),如果涉及侵權(quán)請(qǐng)聯(lián)系站長(zhǎng)郵箱:is@yisu.com進(jìn)行舉報(bào),并提供相關(guān)證據(jù),一經(jīng)查實(shí),將立刻刪除涉嫌侵權(quán)內(nèi)容。