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#求10萬內(nèi)的所有素數(shù)(9592)
print(2)
count = 1
for i in range(3,100000):
for j in range(2,i):
if i%j ==0:
break
if j==i-1:
print(i)
優(yōu)化:
count = 1
for i in range(3,100000,2):#跳過所有偶數(shù)
for j in range(2,i):
if i%j ==0:
break
if j==i-1:
count +=1
print(count)
再優(yōu)化:
count = 1
for i in range(3,100000,2):
for j in range(2,int(i**0.5)+1):#便利到i的開平方
if i%j ==0:
break
else:
count +=1
print(count)
再再優(yōu)化:
#由于數(shù)學成績有限,方法來自網(wǎng)上
count = 2 #大于等于5的素數(shù)一定和6的倍數(shù)相鄰,所以2、3不在循環(huán)內(nèi)統(tǒng)計,
n = 100000
for num in range(4,n):
if num%6 != 1 and num%6 !=5:
continue
else:
snum = int(num**0.5+1)
for i in range(5,snum):
if not num%i:
break
else:
count +=1
print(count)
再再再優(yōu)化:
#求10萬內(nèi)的所有素數(shù)
count = 2 #大于等于5的素數(shù)一定和6的倍數(shù)相鄰,所以2、3不在循環(huán)內(nèi)統(tǒng)計,
n = 100000
for num in range(4,n):
if num%6 != 1 and num%6 !=5:
continue
else:
snum = int(num**0.5+1)
for i in range(5,snum,2):
if not num%i:
break
else:
count +=1
print(count)
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