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本篇文章給大家分享的是有關json串和實體類字段不一致如何解決,小編覺得挺實用的,因此分享給大家學習,希望大家閱讀完這篇文章后可以有所收獲,話不多說,跟著小編一起來看看吧。
首先,我們建立一個實體類:這里簡單定義了name,sex,age三個屬性,以及get set tostring方法。
public class Student { private String name; private String sex; private Integer age; public String getName() { return name; } public String getSex() { return sex; } public Integer getAge() { return age; } public void setName(String name) { this.name = name; } public void setSex(String sex) { this.sex = sex; } public void setAge(Integer age) { this.age = age; } @Override public String toString() { return "Student [name=" + name + ", sex=" + sex + ", age=" + age + "]"; } }
當字段少于實體類字段:正常通過,沒有的字段會被賦予默認值
//fastjson 少字段 @Test public void testFastjson01() { String jsonStr = "{\"age\":18,\"name\":\"zhangsan\"}"; Student stu = JSON.parseObject(jsonStr, Student.class); System.out.println(stu); // Student [name=zhangsan, sex=null, age=18] }
當字段多于實體類字段:正常通過,沒有的字段不會被反序列化到對象中
//fastjson 多字段 @Test public void testFastjson02() { String jsonStr = "{\"age\":20,\"name\":\"lisi\",\"sex\":\"男\(zhòng)",\"hobby\":\"basketball\"}"; Student stu = JSON.parseObject(jsonStr, Student.class); System.out.println(stu); // Student [name=lisi, sex=男, age=20] }
當字段少于實體類字段:正常通過,沒有的字段會被賦予默認值
//jackson 少字段 @Test public void testJackson01() throws Exception{ String jsonStr = "{\"age\":18,\"name\":\"zhangsan\"}"; ObjectMapper om = new ObjectMapper(); Student stu = om.readValue(jsonStr, Student.class); System.out.println(stu); // Student [name=zhangsan, sex=null, age=18] }
當字段多于實體類字段:
//jackson 多字段 @Test public void testJackson02() throws Exception{ String jsonStr = "{\"age\":20,\"name\":\"lisi\",\"sex\":\"男\(zhòng)",\"hobby\":\"basketball\"}"; ObjectMapper om = new ObjectMapper(); Student stu = om.readValue(jsonStr, Student.class); System.out.println(stu); }
此時會報錯,這個錯翻譯過來就是,一個無法識別的field。
com.fasterxml.jackson.databind.exc.UnrecognizedPropertyException: Unrecognized field "hobby" (class com.cyj.demo03.Student), not marked as ignorable (3 known properties: "name", "sex", "age"]) at [Source: {"age":20,"name":"lisi","sex":"男","hobby":"basketball"}; line: 1, column: 44] (through reference chain: com.cyj.demo03.Student["hobby"]) at com.fasterxml.jackson.databind.exc.UnrecognizedPropertyException.from(UnrecognizedPropertyException.java:51) at com.fasterxml.jackson.databind.DeserializationContext.reportUnknownProperty(DeserializationContext.java:817) at com.fasterxml.jackson.databind.deser.std.StdDeserializer.handleUnknownProperty(StdDeserializer.java:958) at com.fasterxml.jackson.databind.deser.BeanDeserializerBase.handleUnknownProperty(BeanDeserializerBase.java:1324) at com.fasterxml.jackson.databind.deser.BeanDeserializerBase.handleUnknownVanilla(BeanDeserializerBase.java:1302) at com.fasterxml.jackson.databind.deser.BeanDeserializer.vanillaDeserialize(BeanDeserializer.java:249) at com.fasterxml.jackson.databind.deser.BeanDeserializer.deserialize(BeanDeserializer.java:136) at com.fasterxml.jackson.databind.ObjectMapper._readMapAndClose(ObjectMapper.java:3564) at com.fasterxml.jackson.databind.ObjectMapper.readValue(ObjectMapper.java:2580) at com.cyj.demo03.TestJson.testJackson02(TestJson.java:40) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:62) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43) at java.lang.reflect.Method.invoke(Method.java:497) at org.junit.runners.model.FrameworkMethod$1.runReflectiveCall(FrameworkMethod.java:50) at org.junit.internal.runners.model.ReflectiveCallable.run(ReflectiveCallable.java:12) at org.junit.runners.model.FrameworkMethod.invokeExplosively(FrameworkMethod.java:47) at org.junit.internal.runners.statements.InvokeMethod.evaluate(InvokeMethod.java:17) at org.junit.runners.ParentRunner.runLeaf(ParentRunner.java:325) at org.junit.runners.BlockJUnit4ClassRunner.runChild(BlockJUnit4ClassRunner.java:78) at org.junit.runners.BlockJUnit4ClassRunner.runChild(BlockJUnit4ClassRunner.java:57) at org.junit.runners.ParentRunner$3.run(ParentRunner.java:290) at org.junit.runners.ParentRunner$1.schedule(ParentRunner.java:71) at org.junit.runners.ParentRunner.runChildren(ParentRunner.java:288) at org.junit.runners.ParentRunner.access$000(ParentRunner.java:58) at org.junit.runners.ParentRunner$2.evaluate(ParentRunner.java:268) at org.junit.runners.ParentRunner.run(ParentRunner.java:363) at org.eclipse.jdt.internal.junit4.runner.JUnit4TestReference.run(JUnit4TestReference.java:86) at org.eclipse.jdt.internal.junit.runner.TestExecution.run(TestExecution.java:38) at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.runTests(RemoteTestRunner.java:538) at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.runTests(RemoteTestRunner.java:760) at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.run(RemoteTestRunner.java:460) at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.main(RemoteTestRunner.java:206)
由此可見,在默認情況下,jackson是不支持json串的字段多于實體類字段的,但是,jackson也提供了解決方案,我們在實體類上,添加注解@JsonIgnoreProperties,這個注解有一個ignoreUnknown屬性,默認值為false,我們可以將它改為true,這樣jackson在反序列化的時候,就會忽略掉不存在的屬性了。(@JsonIgnoreProperties(ignoreUnknown = true))
補充:json字段名不一致的問題
項目開發(fā)過程中,有時候可能要對接第三方平臺,可能就會存在字段名不一樣的問題,而雙方的字段名不一致, 而代碼開發(fā)已經有一段時間勒,如果就因為字段名不一樣的問題,雙方改成屬性名一致,這樣改動量太大,也不保險,下面我來接手一下,針對這種場景,如果解決。
假設: 系統(tǒng)通過http對接,傳的是json。有一個參數"名稱"
第三方平臺:name
開發(fā)環(huán)境:userName
直接通過實體類映射,不用說肯定有問題
@JsonProperty("name") private String userName;
以上就是json串和實體類字段不一致如何解決,小編相信有部分知識點可能是我們日常工作會見到或用到的。希望你能通過這篇文章學到更多知識。更多詳情敬請關注億速云行業(yè)資訊頻道。
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