oracle性能調(diào)優(yōu)學習0622

1. 查詢數(shù)據(jù)庫中的等待事件：

   SET lines 100
   SET pages 10000
   COLUMN wait_class format a12
   COLUMN event format a30
   COLUMN total_waits format 999999
   COLUMN total_us format 999999999
   COLUMN pct_time format 99.99
   COLUMN avg_us format 999999.99
   SET echo on

   SELECT   wait_class, event, total_waits AS waits,
            ROUND (time_waited_micro / 1000) AS total_ms,
            ROUND (time_waited_micro * 100 / SUM (time_waited_micro) OVER (),
                   2
                  ) AS pct_time,
            ROUND ((time_waited_micro / total_waits) / 1000, 2) AS avg_ms
       FROM v$system_event
      WHERE wait_class <> 'Idle'
   ORDER BY time_waited_micro DESC;

2.整合時間模型和等待接口：

SELECT event,
       total_waits,
       round(time_waited_micro / 1000000) AS time_waited_secs,
       round(time_waited_micro * 100 / SUM(time_waited_micro) over(), 2) AS pct_time
  FROM (SELECT event, total_waits, time_waited_micro
          FROM v$system_event
         WHERE wait_class <> 'Idle'
        UNION
        SELECT stat_name, NULL, VALUE
          FROM v$sys_time_model
         WHERE stat_name IN ('DB CPU', 'backup cpu time'))
 ORDER BY 3 DESC

SELECT sample_seconds,
       stat_name,
       waits_per_second        waits_per_sec,
       microseconds_per_second ms_per_sec,
       pct_of_time             pct
  FROM opsg_delta_report
 WHERE microseconds_per_second > 0;
監(jiān)控索引的使用情況：

WITH in_plan_objects AS
 (SELECT DISTINCT object_name FROM v$sql_plan WHERE object_owner = 'SCOTT')
SELECT table_name,
       index_name,
       CASE
         WHEN object_name IS NULL THEN
          'NO'
         ELSE
          'YES'
       END AS in_cached_plan
  FROM user_indexes
  LEFT OUTER JOIN in_plan_objects
    ON (index_name = object_name);

4.識別從綁定變量中獲益的sql語句：

WITH force_matches AS
       (SELECT force_matching_signature,
               COUNT( * )  matches,
               MAX(sql_id || child_number) max_sql_child,
               DENSE_RANK() OVER (ORDER BY COUNT( * ) DESC)
                  ranking
        FROM v$sql
        WHERE force_matching_signature <> 0
          AND parsing_schema_name <> 'SYS'
        GROUP BY force_matching_signature
        HAVING COUNT( * ) > 5)
SELECT sql_id,  matches, parsing_schema_name schema, sql_text
  FROM    v$sql JOIN force_matches
    ON (sql_id || child_number = max_sql_child)
WHERE ranking <= 10
ORDER BY matches DESC;