JAVA怎么求兩個日期的差值

這篇文章主要介紹“JAVA怎么求兩個日期的差值”，在日常操作中，相信很多人在JAVA怎么求兩個日期的差值問題上存在疑惑，小編查閱了各式資料，整理出簡單好用的操作方法，希望對大家解答”JAVA怎么求兩個日期的差值”的疑惑有所幫助！接下來，請跟著小編一起來學(xué)習(xí)吧！

1. import java.util.Scanner;
   

2. class fundemo6{
   

3. public static void main(String[] arg){
   

4.     Scanner s=new Scanner(System.in);
   

5.     System.out.println("Please input first date year:");
   

6.     int y1=s.nextInt();
   

7.     System.out.println("Please input first date month:");
   

8.     int m1=s.nextInt();    
   

9.     System.out.println("Please input first date day:");
   

10.     int d1=s.nextInt();    
    

11.     System.out.println("The first date you input is:"+y1+"-"+m1+"-"+d1);
    

12.     System.out.println("Please input second date year:");
    

13.     int y2=s.nextInt();
    

14.     System.out.println("Please input second date month:");
    

15.     int m2=s.nextInt();    
    

16.     System.out.println("Please input second date day:");
    

17.     int d2=s.nextInt();    
    

18.     System.out.println("The second date you input is:"+y2+"-"+m2+"-"+d2);
    

19.     System.out.println("sub days of two years is:"+subDays(y1,m1,d1,y2,m2,d2));
    

20.     }
    

21. public static int getDays(int y,int m,int d){
    

22.     int sum=0;
    

23.     switch(m-1){
    

24.     case 11:sum+=30;
    

25.     case 10:sum+=31;
    

26.     case 9:sum+=30;
    

27.     case 8:sum+=31;
    

28.     case 7:sum+=31;
    

29.     case 6:sum+=30;
    

30.     case 5:sum+=31;
    

31.     case 4:sum+=30;
    

32.     case 3:sum+=31;
    

33.     case 2:if(isLeap(y))
    

34.                 sum+=29;
    

35.                 else
    

36.                 sum+=28;
    

37.     case 1:sum+=31;
    

38.     }
    

39.     sum+=d;
    

40.     return sum;
    

41.     }
    

42. public static boolean isLeap(int y){
    

43.     if(y%100!=0&&y%4==0||y%400==0)
    

44.         return true;
    

45.         return false;
    

46. }
    

47. public static int otherDays(int y,int m,int d){
    

48.     if(isLeap(y))
    

49.     return 366-getDays(y,m,d);
    

50.     return 365-getDays(y,m,d);
    

51. }
    

52. public static int subDays(int y1,int m1,int d1,int y2,int m2,int d2){
    

53.     if(y1==y1)
    

54.         int day1=getDays(y1,m1,d1)-getDays(y2,m2,d2);
    

55.     return abs(day1);
    

56. }
    

57. public static int abs(int n){
    

58.     return n>=0?n:-n;
    

59. }
    

60. }

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