Oracle如何實現(xiàn)層次化查詢

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Oracle層次化查詢

(1) 樹狀模型

假如有一個市場模型，其中一級市場是中國，二級市場是省份，三級市場是各個省下面的市，四級市場是各個市下面的縣。那么可以創(chuàng)建表market：

create table market(market_id number(2), market_name varchar2(10), parent_market_id number(2));

insert all

into market values(1, 'China', 0)

into market values(2, 'Shan Xi', 1)

into market values(3, 'Shan Dong', 1)

into market values(4, 'Fu Jian', 1)

into market values(5, 'Tai Yuan', 2)

into market values(6, 'Yang Quan', 2)

into market values(7, 'Qi Zhou', 2)

into market values(8, 'Qing Dao', 3)

into market values(9, 'Ji Nan', 3)

into market values(10, 'Yan Tai', 3)

into market values(11, 'Xia Men', 4)

into market values(12, 'Fu Zhou', 4)

into market values(13, 'Quan Zhou', 4)

into market values(14, 'Gu Jiao', 5)

into market values(15, 'Yang Qu', 5)

into market values(16, 'Qing Xu', 5)

select * from dual;

(2) 層次化查詢

select market_id, market_name

from market

start with market_name = 'Shan Xi'

connect by prior market_id = parent_market_id;

MARKET_ID MARKET_NAME

---------- ------------------------------

2 Shan Xi

5 Tai Yuan

14 Gu Jiao

15 Yang Qu

16 Qing Xu

6 Yang Quan

7 Qi Zhou

7 rows selected.

這里的搜索規(guī)則為：從'Shan Xi'節(jié)點開始搜索、前一個節(jié)點的market_id等于下一個節(jié)點的parent_markket_id。

(3) 相關函數(shù)

顯示搜索路徑的函數(shù)為

sys_connect_by_path（列名，分隔符）

示例：

select market_id, market_name, sys_connect_by_path(market_name, '/') as market_path

from market

start with market_name = 'Gu Jiao'

connect by prior parent_market_id = market_id;

MARKET_ID MARKET_NAM MARKET_PATH

---------- ---------- ----------------------------------------

14 Gu Jiao    /Gu Jiao

5 Tai Yuan   /Gu Jiao/Tai Yuan

2 Shan Xi    /Gu Jiao/Tai Yuan/Shan Xi

1 China      /Gu Jiao/Tai Yuan/Shan Xi/China

這里可以利用max()函數(shù)來獲得完整的路徑：

select max(sys_connect_by_path(market_name, '/')) market_path

from market

start with market_name = 'Gu Jiao'

connect by prior parent_market_id = market_id;

MARKET_PATH

----------------------------------------

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