oracle拆分逗號(hào)分隔字符串 實(shí)現(xiàn)split

如果一個(gè)字符串中有像逗號(hào)或其它符號(hào)分隔，你想把它折分成列，如’first field, second field , third field’,
拆成

first field
second field
third field

第一種 用10G開(kāi)始支持的正則表達(dá)式

anbob@ANBOB>SELECT REGEXP_SUBSTR ('first field, second field , third field', '[^,]+', 1,rownum)
  2  FROM DUAL
  3  CONNECT BY ROWNUM <=
  4  LENGTH ('first field, second field , third field') - LENGTH (REPLACE ('first field, second field , third field', ',', ''))+1;

REGEXP_SUBSTR('FIRSTFIELD,SECONDFIELD,THIRDFIELD','[^,]+',1,ROWNUM)
------------------------------------------------------------------------------
first field
second field
third field

TIP:
REGEXP_SUBSTR 函數(shù)是把那個(gè)串以正則不是以,（逗號(hào)）開(kāi)頭的截取，第二個(gè)參數(shù)是取第幾組，rownum偽列序號(hào)，connect 循環(huán) ，循環(huán)次數(shù)為串總長(zhǎng)度-去除分隔符后=幾個(gè)分隔符 +1

第二種用type,function

第一，先創(chuàng)建一個(gè)Type

CREATE OR REPLACE TYPE type_split IS TABLE OF VARCHAR2 (4000)

第二，創(chuàng)建函數(shù)

create or replace function split(p_list varchar2,p_sep varchar2 := ’,’)
return type_split pipelined
IS
l_idx pls_integer;
v_list varchar2(50) := p_list;
begin
 loop
   l_idx := instr(v_list,p_sep);
   if l_idx = 0 then
     pipe row(substr(v_list,1,l_idx-1));
     v_list := substr(v_list,l_idx+length(p_sep));
   else
     pipe row(v_list);
    exit;
   end if;
  end loop;
end split;

第三，調(diào)試

select * from table(split(‘a(chǎn)aa,bbb,ccc’,',’));

拆分列字段

anbob@ANBOB>select * from test11;

                  ID NAME
-------------------- ----------
                   1 a,b,c
                   2 e,d

nbob@ANBOB>with temp0 as (select LEVEL lv from dual CONNECT BY LEVEL <= 100)  
  2       select id,substr(t.vals,instr(t.vals, ',', 1, tv.lv) + 1,  
  3                          instr(t.vals, ',', 1, tv.lv + 1) -(  
  4                          instr(t.vals, ',', 1, tv.lv) + 1)  
  5                   ) AS name  
  6       from (select id,',' || name || ',' AS vals,  
  7                  length(name || ',') - nvl(length(REPLACE(name, ',')), 0) AS cnt  
  8             from test11) t join temp0 tv  
  9                       on  tv.lv <= t.cnt  order by 1;

                  ID NAME
-------------------- ------------------------
                   1 a
                   1 b
                   1 c
                   2 d
                   2 e

擴(kuò)展 regexp_replace

V字段中每個(gè)值中字符串以，分隔，如果不是以9開(kāi)頭那組串加‘00’

anbob@NCME>create table testreg(v varchar2(80));
Table created.
anbob@NCME>insert into testreg values(’911,000,12,31′);
1 row created.

anbob@NCME>insert into testreg values(’11911,554000,312,931′);
1 row created.

anbob@NCME>commit;
Commit complete.

anbob@NCME>select ltrim(regexp_replace(‘,’||v,’([,])’,'\100′),’,') newv,v from testreg;

NEWV V
—————————— ——————————
00911,00000,0012,0031 911,000,12,31
0011911,00554000,00312,00931 11911,554000,312,931