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oracle中如何刪除重數(shù)據(jù)

發(fā)布時間:2021-07-27 15:41:09 來源:億速云 閱讀:152 作者:Leah 欄目:關(guān)系型數(shù)據(jù)庫

今天就跟大家聊聊有關(guān)oracle中如何刪除重數(shù)據(jù),可能很多人都不太了解,為了讓大家更加了解,小編給大家總結(jié)了以下內(nèi)容,希望大家根據(jù)這篇文章可以有所收獲。

前期準(zhǔn)備

創(chuàng)建測試表

create table salary( 

  staffid   int, 

  staff   varchar(15)  

);

模擬重復(fù)數(shù)據(jù)

insert into salary values(1,'a');

insert into salary values(2,'s');

insert into salary values(3,'ert');

insert into salary values(4,'d');

insert into salary values(5,'b');

insert into salary values(1,'a');

insert into salary values(2,'s');

insert into salary values(3,'ert');

insert into salary values(4,'d');

insert into salary values(5,'b');

insert into salary values(1,'a');

insert into salary values(2,'s');

insert into salary values(3,'ert');

insert into salary values(4,'d');

insert into salary values(5,'b');

insert into salary values(10,'aaaa');

insert into salary values(20,'sass');

insert into salary values(30,'erwt');

insert into salary values(40,'dsd');

insert into salary values(50,'bsdf');

insert into salary values(1,'oookkk');

實驗一:模擬單個字段數(shù)據(jù)重復(fù)

select * from salary;

STAFFID STAFF

--------------- ---------------

              1 oookkk

              1 a

              2 s

              3 ert

              4 d

              5 b

              1 a

              2 s

              3 ert

              4 d

              5 b

              1 a

              2 s

              3 ert

              4 d

              5 b

             10 aaaa

             20 sass

             30 erwt

             40 dsd

             50 bsdf

21 rows selected

1.查出重復(fù)數(shù)據(jù)

方法一

SELECT *

FROM salary a

WHERE ((SELECT COUNT(*)

          FROM salary

          WHERE staffid = a.staffid) > 1)

ORDER BY staffid 

方法二

select *

  from salary

 where staffid in

(select staffid from salary group by staffid having count(staffid) > 1)

刪除重復(fù)數(shù)據(jù),只保留1條,其余全部刪除

方法一,通過rowid刪除

delete from salary

where staffid in (select staffid from salary group by staffid  having count(staffid) > 1)

and rowid not in (select min(rowid) from salary group by staffid having count(staffid )>1)

實驗二:模擬兩個個字段數(shù)據(jù)重復(fù)

1.查詢重復(fù)記錄

方法一

select * from salary a

where (a.staffid,a.staff) in (select staffid,staff from salary group by staffid,staff having count(*) > 1)

方法二

SELECT *

FROM salary a

WHERE ((SELECT COUNT(*)

          FROM salary

          WHERE staffid = a.staffid and staff=a.staff) > 1)

ORDER BY staffid 

結(jié)果,共15條

STAFFIDSTAFF

1      a

1      a

1      a

2      s

2      s

2      s

3      ert

3      ert

3      ert

4      d

4      d

4      d

5      b

5      b

5      b

2.刪除重復(fù)數(shù)據(jù),只保留1條,其余全部刪除

delete from vitae a

where (a.peopleId,a.seq) in   (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)

and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)

3.查看刪除后結(jié)果

select * from salary;

結(jié)果

STAFFIDSTAFF

1      oookkk

1      a

2      s

3      ert

4      d

5      b

10    aaaa

20    sass

30    erwt

40    dsd

50    bsdf

看完上述內(nèi)容,你們對oracle中如何刪除重數(shù)據(jù)有進(jìn)一步的了解嗎?如果還想了解更多知識或者相關(guān)內(nèi)容,請關(guān)注億速云行業(yè)資訊頻道,感謝大家的支持。

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