python實現(xiàn)猜單詞小游戲的方法

#!/usr/bin/python 
# -*- coding: utf-8 -*- 
 
from __future__ import print_function 
import os 
import sys 
import random 
import time 
 
#單詞庫 
Words = ['apple','pear','banana'] 
 
#單詞隨機選擇函數(shù) 
def getRandomWord(): 
 global Words 
 return Words[random.randint(0,len(Words)-1)] 
  
#猜測流程 
def getGuess(): 
 while True: 
  guess = raw_input("Guess the Word: ") 
  for letter in guess: 
   if letter in wrongLetters: 
    print("The char: " + letter + " you have already guessed") 
    continue 
   
  break 
 return guess 
  
#判別顯示流程 
def displayGame(secretLetters,wrongLetters,secretWord): 
 global guess 
 global count 
 print("Info: ") 
 for letter in guess: 
  if letter in secretWord: 
   secretLetters += letter 
  else: 
   wrongLetters += letter 
  
 print("SecretLetters: ",end = '') 
 for letter in secretLetters: 
  print(letter,end = ' ') 
 print() 
  
 print("WrongLetters: ",end = '') 
 for letter in wrongLetters: 
  print(letter,end = ' ') 
 print() 
 print("Count: "+str(count)) 
 blanks = '_'*len(secretWord) 
 for i in range(len(guess)): 
  if i >=len(secretWord): 
   break 
  if secretWord[i]==guess[i]: 
   blanks = blanks[:i] + secretWord[i] + blanks[i+1:] 
 print("Word: ",end = '') 
 for i in blanks: 
  print(i,end=" ") 
 print() 
 print() 
  
  
#主流程  
  
secretLetters = '' 
wrongLetters = '' 
secretWord = '' 
guess = "" 
count = 6 
 
os.system('cls') 
secretWord = getRandomWord() 
while True: 
 displayGame(secretLetters,wrongLetters,secretWord) 
 guess = getGuess() 
 if guess == secretWord: 
  print ("You win !") 
  break 
 else: 
  if count <= 0: 
   print("You lose !") 
   break 
  else: 
   count -= 1 
   continue