Python中的正則表達(dá)式與JSON數(shù)據(jù)交換格式

import re
a='C|C++|Java|C#||Python|Javascript'
r= re.findall('Python',a)
print(r)
if len(r) > 0:
 print('字符串中包含Python')
else:
 print('No')
['Python']
字符串中包含Python 

import re
a='C0C++7Java8C#9Python6Javascript'
r= re.findall('\d',a)
print(r)
b=''
for x in a:
 try:
 int(x)
 b +=x+','
 except :
 pass
print(b)

import re
#找出中間一個(gè)字符不是C 和F的 單詞
s = 'abc, acc, adc, aec, afc, ahc'
r = re.findall('a[^cf]c', s) #[a-z] [cf]
print(r)

#\d 數(shù)字 \D 字母
#\w 數(shù)字和字母 =[a-zA-Z0-9_] \W 
#\s 空白字符 \S
a='python 11\t11java&678p\nh\rp'
r = re.findall('\s', a)
print(r)

a='python 1111java&678php'
r = re.findall('[a-z]{3,6}', a)
print(r)

a='python 1111java&678php'
r = re.findall('[a-z]{3,6}?', a)
#貪婪 與 非貪婪 ?
print(r)

# * 匹配0次或者無(wú)限多次
# + 匹配1次或者無(wú)限多次
# ? 匹配0次或者1次
a='pytho0python1pythonn2pythonw'
r = re.findall('python*', a)
print(r)

qq = '12345678'
# 4~8 
r = re.findall('^\d{4,8}$', qq)
print(r)
a = '123456789'
# 4~8 ^規(guī)則$ ^開頭 $結(jié)尾
e = re.findall('^\d{4,8}$', a)
print(e)

# () 組
a = 'pythonpythonpythonpythonpython'
# 
r = re.findall('(python){3}', a)
print(r)

# I | S 忽略大小寫 | 匹配所有字符
lanuage = 'PythonC#\nJavaPHP'
r = re.findall('c#.{1}', lanuage,re.I | re.S)
print(r)

def convert(value):
 matched = value.group()
 # print(value) <_sre.SRE_Match object; span=(6, 8), match='C#'>
 return '!!'+matched+'!!'
lanuage = 'PythonC#JavaC#PHPC#'
# r = re.sub('C#', 'GO', lanuage, 1) 返回結(jié)果： PythonGOJavaC#PHPC#
# s=lanuage.replace('C#', 'GO')
r = re.sub('C#', convert, lanuage) #傳入?yún)?shù)
print(r)

def convert(value):
 matched = value.group() #拿到對(duì)象的值
 # print(value) <_sre.SRE_Match object; span=(6, 8), match='C#'>
 if int(matched) >=6 :
 return '9'
 else:
 return '0'
lanuage = 'A8C3721D86'
r = re.sub('\d', convert, lanuage)
print(r)
#
A9C0900D99

s = 'A8C3721D86'
# None 從開頭開始匹配 假如沒有找到相應(yīng)的匹配結(jié)果 返回None 只匹配一次
r = re.match('\d', s) 
print(r) #None
#搜索這個(gè)字符串 一旦找到第一個(gè)滿足匹配的結(jié)果就返回 只匹配一次
r1 = re.search('\d', s)
print(r1) #<_sre.SRE_Match object; span=(1, 2), match='8'>
print(r1.group()) #8
print(r1.span()) # (1, 2)
r2 = re.findall('\d', s)
print(r2) #['8', '3', '7', '2', '1', '8', '6']

#提取life 和python 之間的值
s = 'life is short,i use python'
#None
r = re.search('life.*python', s)
print(r.group()) #life is short,i use python group(組號(hào))
r = re.search('life(.*)python', s)
print(r.group(0)) #life is short,i use python group(組號(hào))
print(r.group(1)) # is short,i use
#group(0) 一種特殊情況 匹配正則表達(dá)式完整的結(jié)果
r = re.findall('life(.*)python', s)
print(r) #[' is short,i use ']
s = 'life is short,i use python, i love python'
r = re.search('life(.*)python(.*)python', s)
print(r.group(0)) # life is short,i use python, i love python 
print(r.group(1)) # is short,i use
print(r.group(2)) # , i love
print(r.group(0,1,2)) #('life is short,i use python, i love python', ' is short,i use ', ', i love ')
print(r.groups()) # (' is short,i use ', ', i love ')

#\d 數(shù)字 \D 字母
#\w 數(shù)字和字母 =[a-zA-Z0-9_] \W 
#\s 空白字符 \S
# . 匹配除了換行符\n之外其他所有字符
# * 匹配0次或者無(wú)限多次
# + 匹配1次或者無(wú)限多次
# ? 匹配0次或者1次
# () 組 
# I | S 忽略大小寫 | 匹配所有字符

import json
# JSON object array
json_str = '{"name":"qiyue","age":18}'
s = json.loads(json_str)
# dict
#反序列化
s = json.loads(json_str) #load() 把json 的數(shù)據(jù)類型 轉(zhuǎn)換為我們自己語(yǔ)言的數(shù)據(jù)類型
print(type(s)) #<class 'dict'>
print(s) #{'name': 'qiyue', 'age': 18}
print(s['name']) # qiyue
json_str = '[{"name":"qiyue","age":18},{"name":"qiyue","age":18}]'
s = json.loads(json_str)
print(type(s)) # <class 'list'>
print(s) # [{'name': 'qiyue', 'age': 18}, {'name': 'qiyue', 'age': 18}]

JSON Python
object dict
array list
string str
number int
number float
true True
false False
null None

#序列化 為json
student = [
 {"name":"qiyue","age":18, 'flag':False},
 {"name":"python","age":18}
]
json_str = json.dumps(student)
print(type(json_str)) # <class 'str'>
print(json_str) #[{"name": "qiyue", "age": 18, "flag": false}, {"name": "python", "age": 18}]