您好,登錄后才能下訂單哦!
這篇文章主要介紹python怎么實(shí)現(xiàn)兩個(gè)經(jīng)緯度點(diǎn)之間的距離和方位角的方法,文中介紹的非常詳細(xì),具有一定的參考價(jià)值,感興趣的小伙伴們一定要看完!
1. 求兩個(gè)經(jīng)緯點(diǎn)的方位角,P0(latA, lonA), P1(latB, lonB)(很多博客寫(xiě)的不是很好,這里總結(jié)一下)
def getDegree(latA, lonA, latB, lonB): """ Args: point p1(latA, lonA) point p2(latB, lonB) Returns: bearing between the two GPS points, default: the basis of heading direction is north """ radLatA = radians(latA) radLonA = radians(lonA) radLatB = radians(latB) radLonB = radians(lonB) dLon = radLonB - radLonA y = sin(dLon) * cos(radLatB) x = cos(radLatA) * sin(radLatB) - sin(radLatA) * cos(radLatB) * cos(dLon) brng = degrees(atan2(y, x)) brng = (brng + 360) % 360 return brng
2. 求兩個(gè)經(jīng)緯點(diǎn)的距離函數(shù):P0(latA, lonA), P1(latB, lonB)
def getDistance(latA, lonA, latB, lonB): ra = 6378140 # radius of equator: meter rb = 6356755 # radius of polar: meter flatten = (ra - rb) / ra # Partial rate of the earth # change angle to radians radLatA = radians(latA) radLonA = radians(lonA) radLatB = radians(latB) radLonB = radians(lonB) pA = atan(rb / ra * tan(radLatA)) pB = atan(rb / ra * tan(radLatB)) x = acos(sin(pA) * sin(pB) + cos(pA) * cos(pB) * cos(radLonA - radLonB)) c1 = (sin(x) - x) * (sin(pA) + sin(pB))**2 / cos(x / 2)**2 c2 = (sin(x) + x) * (sin(pA) - sin(pB))**2 / sin(x / 2)**2 dr = flatten / 8 * (c1 - c2) distance = ra * (x + dr) return distance
以上是“python怎么實(shí)現(xiàn)兩個(gè)經(jīng)緯度點(diǎn)之間的距離和方位角的方法”這篇文章的所有內(nèi)容,感謝各位的閱讀!希望分享的內(nèi)容對(duì)大家有幫助,更多相關(guān)知識(shí),歡迎關(guān)注億速云行業(yè)資訊頻道!
免責(zé)聲明:本站發(fā)布的內(nèi)容(圖片、視頻和文字)以原創(chuàng)、轉(zhuǎn)載和分享為主,文章觀點(diǎn)不代表本網(wǎng)站立場(chǎng),如果涉及侵權(quán)請(qǐng)聯(lián)系站長(zhǎng)郵箱:is@yisu.com進(jìn)行舉報(bào),并提供相關(guān)證據(jù),一經(jīng)查實(shí),將立刻刪除涉嫌侵權(quán)內(nèi)容。