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JavaScript實現五子棋游戲的方法詳解

發(fā)布時間:2021-04-12 10:36:08 來源:億速云 閱讀:164 作者:小新 欄目:web開發(fā)

這篇文章將為大家詳細講解有關JavaScript實現五子棋游戲的方法詳解,小編覺得挺實用的,因此分享給大家做個參考,希望大家閱讀完這篇文章后可以有所收獲。

效果圖:

JavaScript實現五子棋游戲的方法詳解

五子棋素材圖:

JavaScript實現五子棋游戲的方法詳解

代碼:

<!DOCTYPE html>
<html>
<head>
  <meta charset="utf-8">
  <meta http-equiv="X-UA-Compatible" content="IE=edge">
  <title>HTML五子棋游戲</title>
  <link rel="stylesheet" href="">
  <script>
    //五子棋的構造函數
    function Game(){
      this.isWin = false;//游戲是否結束標志
    }
    //閉包計棋器
    Game.cnt = (function(){
      var curr = 'black';
      return function(){
        var tmp = curr;
        if(curr == 'black'){
          curr = 'white';
        }else{
          curr = 'black';
        }
        return tmp;
      }
    })();
    //下棋函數
    Game.xiaQi = function(g){
      //判斷選擇的位置是否已經下過棋了
      if(this.style.backgroundImage.indexOf('gif') >= 0){
        alert('這里已經下過棋了');
        return ;
      }
      var color = Game.cnt();
      this.style.backgroundImage = "url(./images/"+color+".gif)";
      Game.judge.call(this,color,g);//判定函數
    }
    //判定游戲是否結束
    Game.judge = function(color,g){
      var tds = document.getElementsByTagName('td');
      //獲取當前棋子所下的位置
      var curr = {x:this.cellIndex,y:this.parentElement.rowIndex,color:color};
      var line = ['','','',''];//表示當前棋子的橫、豎、左斜、右斜方向的棋子
      //遍歷255個棋格,看看是否能贏
      for(var i=0,tmp={};i<tds.length;i++){
        tmp = {x:tds[i].cellIndex,y:tds[i].parentElement.rowIndex,color:'0'};
        if(tds[i].style.backgroundImage.indexOf('black') >= 0){
          tmp.color = 'b';
        }else if(tds[i].style.backgroundImage.indexOf('white') >= 0){
          tmp.color = 'w';
        }
        //獲取當前棋子的橫向其他棋子的坐落情況
        if(curr.y == tmp.y){
          line[0] += tmp.color;
        }
        //獲取當前棋子的豎向其他棋子的坐落情況
        if(curr.x == tmp.x){
          line[1] += tmp.color;
        }
        //獲取當前棋子的左斜方向其他棋子的坐落情況
        if(curr.x+curr.y == tmp.x+tmp.y){
          line[2] += tmp.color;
        }
        //獲取當前棋子的右斜方向其他棋子的坐落情況
        if(curr.x-tmp.x == curr.y-tmp.y){
          line[3] += tmp.color;
        }
      }
      color = color == 'black'?'bbbbb':'wwwww';
      //判斷是否五子連珠
      for(var i=0;i<line.length;i++){
        if(line[i].indexOf(color) >=0){
          alert('你贏了');
          g.isWin = true;
          break;
        }
      }
    }
    //頁面加載完成
    window.onload = function(){
      var g = new Game();
      document.getElementsByTagName('table')[0].onclick = function(ev){
        //判斷是否已經贏得游戲
        if(g.isWin){
          alert('此局已結束,請重新開始');
          return;
        }
        Game.xiaQi.call(ev.srcElement,g);//下棋
      }
    }
  </script>
</head>
<style>
  table{
  border-collapse:collapse;
  width:540px;
  height:540px;
  border:solid 1px blue;
  margin:auto;
  background-image: url('./images/background.gif');
}
</style>
<body>
<table>
  <tr>
    <td>&nbsp;</td>
    <td>&nbsp;</td>
    <td>&nbsp;</td>
    <td>&nbsp;</td>
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  </tr>
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  </tr>
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</table>
</body>
</html>

今天不知道怎么搞的,寫博客的時候上傳不了圖片,還好我機智,把圖片存到GitHub上,好了,來講代碼。首先,我必須先說明一下,我覺得代碼還有很大的優(yōu)化空間,感興趣的同學可以繼續(xù)研究。

實現思路:首先創(chuàng)建一個表格,共15行,15列,把背景改成棋盤的圖片,給這個table添加onclick事件,這里使用到了事件委托,事件委托我在之前的文章有介紹過,感興趣的同學可以去看看。去調用xiaQi函數,在下棋函數中,先判斷選擇的位置是否已經下過棋了,使用閉包獲取下一個棋子的顏色,然后調用judge函數,在函數中先獲取當前棋子所下的位置,遍歷255個棋格,看看是否能贏,判斷是否五子連珠,如果有則游戲結束。

關于“JavaScript實現五子棋游戲的方法詳解”這篇文章就分享到這里了,希望以上內容可以對大家有一定的幫助,使各位可以學到更多知識,如果覺得文章不錯,請把它分享出去讓更多的人看到。

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