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Ruby哈希操作如何更新數(shù)據(jù)

小樊
83
2024-11-06 03:00:38
欄目: 編程語言

在Ruby中,哈希(Hash)是一種可變的、無序的鍵值對集合。要更新哈希中的數(shù)據(jù),可以使用以下方法:

  1. 直接通過鍵值更新:
hash = { "a" => 1, "b" => 2, "c" => 3 }
hash["a"] = 10
puts hash # 輸出:{"a"=>10, "b"=>2, "c"=>3}
  1. 使用[]=運算符更新:
hash = { "a" => 1, "b" => 2, "c" => 3 }
hash["a"] = 10
puts hash # 輸出:{"a"=>10, "b"=>2, "c"=>3}
  1. 使用update方法更新哈希:
hash = { "a" => 1, "b" => 2, "c" => 3 }
hash.update("a" => 10)
puts hash # 輸出:{"a"=>10, "b"=>2, "c"=>3}
  1. 使用merge方法更新哈希:
hash = { "a" => 1, "b" => 2, "c" => 3 }
hash.merge!("a" => 10)
puts hash # 輸出:{"a"=>10, "b"=>2, "c"=>3}

注意:update方法會修改原始哈希,而merge方法會返回一個新的哈希,原始哈希保持不變。

  1. 使用[]=運算符更新多個鍵值對:
hash = { "a" => 1, "b" => 2, "c" => 3 }
hash["a"] = 10
hash["b"] = 20
hash["c"] = 30
puts hash # 輸出:{"a"=>10, "b"=>20, "c"=>30}
  1. 使用merge方法更新多個鍵值對:
hash = { "a" => 1, "b" => 2, "c" => 3 }
hash.merge!("a" => 10, "b" => 20, "c" => 30)
puts hash # 輸出:{"a"=>10, "b"=>20, "c"=>30}
  1. 使用塊更新哈希中的多個鍵值對:
hash = { "a" => 1, "b" => 2, "c" => 3 }
hash.merge! do |key, old_value, new_value|
  if key == "a"
    new_value * 2
  else
    old_value
  end
end
puts hash # 輸出:{"a"=>20, "b"=>2, "c"=>3}

這些方法允許您根據(jù)需要更新哈希中的數(shù)據(jù)。

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